(7x+1)(7x-1)=0

Solution for (7x+1)(7x-1)=0 equation:

Simplifying
(7x + 1)(7x + -1) = 0

Reorder the terms:
(1 + 7x)(7x + -1) = 0

Reorder the terms:
(1 + 7x)(-1 + 7x) = 0

Multiply (1 + 7x) * (-1 + 7x)
(1(-1 + 7x) + 7x * (-1 + 7x)) = 0
((-1 * 1 + 7x * 1) + 7x * (-1 + 7x)) = 0
((-1 + 7x) + 7x * (-1 + 7x)) = 0
(-1 + 7x + (-1 * 7x + 7x * 7x)) = 0
(-1 + 7x + (-7x + 49x2)) = 0

Combine like terms: 7x + -7x = 0
(-1 + 0 + 49x2) = 0
(-1 + 49x2) = 0

Solving
-1 + 49x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 49x2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 49x2 = 0 + 1
49x2 = 0 + 1

Combine like terms: 0 + 1 = 1
49x2 = 1

Divide each side by '49'.
x2 = 0.02040816327

Simplifying
x2 = 0.02040816327

Take the square root of each side:
x = {-0.142857143, 0.142857143}