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(7x+1)(9x-7)=360
We move all terms to the left:
(7x+1)(9x-7)-(360)=0
We multiply parentheses ..
(+63x^2-49x+9x-7)-360=0
We get rid of parentheses
63x^2-49x+9x-7-360=0
We add all the numbers together, and all the variables
63x^2-40x-367=0
a = 63; b = -40; c = -367;
Δ = b2-4ac
Δ = -402-4·63·(-367)
Δ = 94084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{94084}=\sqrt{4*23521}=\sqrt{4}*\sqrt{23521}=2\sqrt{23521}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-2\sqrt{23521}}{2*63}=\frac{40-2\sqrt{23521}}{126} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+2\sqrt{23521}}{2*63}=\frac{40+2\sqrt{23521}}{126} $
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