(7x+1)/5=(4x+1)/3

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Solution for (7x+1)/5=(4x+1)/3 equation:



(7x+1)/5=(4x+1)/3
We move all terms to the left:
(7x+1)/5-((4x+1)/3)=0
We calculate fractions
7x/()+(-((4x+1)*5)/()=0
We calculate terms in parentheses: +(-((4x+1)*5)/(), so:
-((4x+1)*5)/(
We multiply all the terms by the denominator
-((4x+1)*5)
We calculate terms in parentheses: -((4x+1)*5), so:
(4x+1)*5
We multiply parentheses
20x+5
Back to the equation:
-(20x+5)
We get rid of parentheses
-20x-5
Back to the equation:
+(-20x-5)
We get rid of parentheses
7x/()-20x-5=0
We multiply all the terms by the denominator
7x-20x*()-5*()=0
We add all the numbers together, and all the variables
7x-20x*()=0

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