(7x+1)/5=(4x+1)/3

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Solution for (7x+1)/5=(4x+1)/3 equation: 



(7x+1)/5=(4x+1)/3

We move all terms to the left:

(7x+1)/5-((4x+1)/3)=0

We calculate fractions


7x/()+(-((4x+1)*5)/()=0



We calculate terms in parentheses: +(-((4x+1)*5)/(), so:

-((4x+1)*5)/(

We multiply all the terms by the denominator


-((4x+1)*5)



We calculate terms in parentheses: -((4x+1)*5), so:

(4x+1)*5

We multiply parentheses

20x+5

Back to the equation:

-(20x+5)



We get rid of parentheses

-20x-5

Back to the equation:

+(-20x-5)



We get rid of parentheses

7x/()-20x-5=0

We multiply all the terms by the denominator


7x-20x*()-5*()=0

We add all the numbers together, and all the variables

7x-20x*()=0

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