(7x+11)+(2x+2)+(4x-28)=180

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Solution for (7x+11)+(2x+2)+(4x-28)=180 equation: 



(7x+11)+(2x+2)+(4x-28)=180

We move all terms to the left:

(7x+11)+(2x+2)+(4x-28)-(180)=0

We get rid of parentheses

7x+2x+4x+11+2-28-180=0

We add all the numbers together, and all the variables

13x-195=0

We move all terms containing x to the left, all other terms to the right

13x=195

x=195/13

x=15

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