(7x+11+2x+2+4x-28=180,x)

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Solution for (7x+11+2x+2+4x-28=180,x) equation: 



(7x+11+2x+2+4x-28=180.x)

We move all terms to the left:

(7x+11+2x+2+4x-28-(180.x))=0

We add all the numbers together, and all the variables

(7x+11+2x+2+4x-28-(+180.x))=0



We calculate terms in parentheses: +(7x+11+2x+2+4x-28-(+180.x)), so:

7x+11+2x+2+4x-28-(+180.x)

determiningTheFunctionDomain
7x+2x+4x-(+180.x)+11+2-28

We add all the numbers together, and all the variables

13x-(+180.x)-15

We get rid of parentheses

13x-180.x-15

We add all the numbers together, and all the variables

-167x-15

Back to the equation:

+(-167x-15)



We get rid of parentheses

-167x-15=0

We move all terms containing x to the left, all other terms to the right

-167x=15

x=15/-167

x=-15/167

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