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(7x+12)/(4x+3)=2/3
We move all terms to the left:
(7x+12)/(4x+3)-(2/3)=0
Domain of the equation: (4x+3)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
4x!=-3
x!=-3/4
x!=-3/4
x∈R
(7x+12)/(4x+3)-(+2/3)=0
We get rid of parentheses
(7x+12)/(4x+3)-2/3=0
We calculate fractions
(21x+36)/(12x+9)+(-8x-6)/(12x+9)=0
We multiply all the terms by the denominator
(21x+36)+(-8x-6)=0
We get rid of parentheses
21x-8x+36-6=0
We add all the numbers together, and all the variables
13x+30=0
We move all terms containing x to the left, all other terms to the right
13x=-30
x=-30/13
x=-2+4/13
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