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(7x+14)(-x-3)=0
We add all the numbers together, and all the variables
(7x+14)(-1x-3)=0
We multiply parentheses ..
(-7x^2-21x-14x-42)=0
We get rid of parentheses
-7x^2-21x-14x-42=0
We add all the numbers together, and all the variables
-7x^2-35x-42=0
a = -7; b = -35; c = -42;
Δ = b2-4ac
Δ = -352-4·(-7)·(-42)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-7}{2*-7}=\frac{28}{-14} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+7}{2*-7}=\frac{42}{-14} =-3 $
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