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(7x+14)(2x-6)=0
We multiply parentheses ..
(+14x^2-42x+28x-84)=0
We get rid of parentheses
14x^2-42x+28x-84=0
We add all the numbers together, and all the variables
14x^2-14x-84=0
a = 14; b = -14; c = -84;
Δ = b2-4ac
Δ = -142-4·14·(-84)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4900}=70$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-70}{2*14}=\frac{-56}{28} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+70}{2*14}=\frac{84}{28} =3 $
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