(7x+15)(18x+19)=0

Solution for (7x+15)(18x+19)=0 equation:

(7x+15)(18x+19)=0

We multiply parentheses ..

(+126x^2+133x+270x+285)=0

We get rid of parentheses

126x^2+133x+270x+285=0

We add all the numbers together, and all the variables

126x^2+403x+285=0

a = 126; b = 403; c = +285;
Δ = b2-4ac
Δ = 4032-4·126·285
Δ = 18769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18769}=137$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(403)-137}{2*126}=\frac{-540}{252}
=-2+1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(403)+137}{2*126}=\frac{-266}{252}
=-1+1/18
$