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(7x+15)(7x+15)=48
We move all terms to the left:
(7x+15)(7x+15)-(48)=0
We multiply parentheses ..
(+49x^2+105x+105x+225)-48=0
We get rid of parentheses
49x^2+105x+105x+225-48=0
We add all the numbers together, and all the variables
49x^2+210x+177=0
a = 49; b = 210; c = +177;
Δ = b2-4ac
Δ = 2102-4·49·177
Δ = 9408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9408}=\sqrt{3136*3}=\sqrt{3136}*\sqrt{3}=56\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(210)-56\sqrt{3}}{2*49}=\frac{-210-56\sqrt{3}}{98} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(210)+56\sqrt{3}}{2*49}=\frac{-210+56\sqrt{3}}{98} $
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