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(7x+16)(3x+48)=180
We move all terms to the left:
(7x+16)(3x+48)-(180)=0
We multiply parentheses ..
(+21x^2+336x+48x+768)-180=0
We get rid of parentheses
21x^2+336x+48x+768-180=0
We add all the numbers together, and all the variables
21x^2+384x+588=0
a = 21; b = 384; c = +588;
Δ = b2-4ac
Δ = 3842-4·21·588
Δ = 98064
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{98064}=\sqrt{144*681}=\sqrt{144}*\sqrt{681}=12\sqrt{681}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(384)-12\sqrt{681}}{2*21}=\frac{-384-12\sqrt{681}}{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(384)+12\sqrt{681}}{2*21}=\frac{-384+12\sqrt{681}}{42} $
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