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(7x+2)(6x+9)=170
We move all terms to the left:
(7x+2)(6x+9)-(170)=0
We multiply parentheses ..
(+42x^2+63x+12x+18)-170=0
We get rid of parentheses
42x^2+63x+12x+18-170=0
We add all the numbers together, and all the variables
42x^2+75x-152=0
a = 42; b = 75; c = -152;
Δ = b2-4ac
Δ = 752-4·42·(-152)
Δ = 31161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(75)-\sqrt{31161}}{2*42}=\frac{-75-\sqrt{31161}}{84} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(75)+\sqrt{31161}}{2*42}=\frac{-75+\sqrt{31161}}{84} $
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