(7x+2)(x+14)=0

Solution for (7x+2)(x+14)=0 equation:

(7x+2)(x+14)=0

We multiply parentheses ..

(+7x^2+98x+2x+28)=0

We get rid of parentheses

7x^2+98x+2x+28=0

We add all the numbers together, and all the variables

7x^2+100x+28=0

a = 7; b = 100; c = +28;
Δ = b2-4ac
Δ = 1002-4·7·28
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-96}{2*7}=\frac{-196}{14}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+96}{2*7}=\frac{-4}{14}
=-2/7
$