(7x+2)=(5x-3)/6

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Solution for (7x+2)=(5x-3)/6 equation: 



(7x+2)=(5x-3)/6

We move all terms to the left:

(7x+2)-((5x-3)/6)=0

We get rid of parentheses

7x-((5x-3)/6)+2=0

We multiply all the terms by the denominator


7x*6)-((5x-3)+2*6)=0

We add all the numbers together, and all the variables

7x*6)-((5x-3)=0

Wy multiply elements

42x^2=0

a = 42; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·42·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{84}=0$

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