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(7x+26)(4x+37)=85
We move all terms to the left:
(7x+26)(4x+37)-(85)=0
We multiply parentheses ..
(+28x^2+259x+104x+962)-85=0
We get rid of parentheses
28x^2+259x+104x+962-85=0
We add all the numbers together, and all the variables
28x^2+363x+877=0
a = 28; b = 363; c = +877;
Δ = b2-4ac
Δ = 3632-4·28·877
Δ = 33545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(363)-\sqrt{33545}}{2*28}=\frac{-363-\sqrt{33545}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(363)+\sqrt{33545}}{2*28}=\frac{-363+\sqrt{33545}}{56} $
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