(7x+3)(1-4x)=0

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Solution for (7x+3)(1-4x)=0 equation:



(7x+3)(1-4x)=0
We add all the numbers together, and all the variables
(7x+3)(-4x+1)=0
We multiply parentheses ..
(-28x^2+7x-12x+3)=0
We get rid of parentheses
-28x^2+7x-12x+3=0
We add all the numbers together, and all the variables
-28x^2-5x+3=0
a = -28; b = -5; c = +3;
Δ = b2-4ac
Δ = -52-4·(-28)·3
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-19}{2*-28}=\frac{-14}{-56} =1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+19}{2*-28}=\frac{24}{-56} =-3/7 $

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