(7x+3)(5x+-2)=3504

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Solution for (7x+3)(5x+-2)=3504 equation:



(7x+3)(5x+-2)=3504
We move all terms to the left:
(7x+3)(5x+-2)-(3504)=0
We add all the numbers together, and all the variables
(7x+3)(5x-2)-3504=0
We multiply parentheses ..
(+35x^2-14x+15x-6)-3504=0
We get rid of parentheses
35x^2-14x+15x-6-3504=0
We add all the numbers together, and all the variables
35x^2+x-3510=0
a = 35; b = 1; c = -3510;
Δ = b2-4ac
Δ = 12-4·35·(-3510)
Δ = 491401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{491401}=701$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-701}{2*35}=\frac{-702}{70} =-10+1/35 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+701}{2*35}=\frac{700}{70} =10 $

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