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(7x+3)(7x+6)=
We move all terms to the left:
(7x+3)(7x+6)-()=0
We add all the numbers together, and all the variables
(7x+3)(7x+6)=0
We multiply parentheses ..
(+49x^2+42x+21x+18)=0
We get rid of parentheses
49x^2+42x+21x+18=0
We add all the numbers together, and all the variables
49x^2+63x+18=0
a = 49; b = 63; c = +18;
Δ = b2-4ac
Δ = 632-4·49·18
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-21}{2*49}=\frac{-84}{98} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+21}{2*49}=\frac{-42}{98} =-3/7 $
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