(7x+3)(8x+1)=180

Solution for (7x+3)(8x+1)=180 equation:

(7x+3)(8x+1)=180

We move all terms to the left:

(7x+3)(8x+1)-(180)=0

We multiply parentheses ..

(+56x^2+7x+24x+3)-180=0

We get rid of parentheses

56x^2+7x+24x+3-180=0

We add all the numbers together, and all the variables

56x^2+31x-177=0

a = 56; b = 31; c = -177;
Δ = b2-4ac
Δ = 312-4·56·(-177)
Δ = 40609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{40609}}{2*56}=\frac{-31-\sqrt{40609}}{112}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{40609}}{2*56}=\frac{-31+\sqrt{40609}}{112}
$