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(7x+3)(9x-1)=0
We multiply parentheses ..
(+63x^2-7x+27x-3)=0
We get rid of parentheses
63x^2-7x+27x-3=0
We add all the numbers together, and all the variables
63x^2+20x-3=0
a = 63; b = 20; c = -3;
Δ = b2-4ac
Δ = 202-4·63·(-3)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-34}{2*63}=\frac{-54}{126} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+34}{2*63}=\frac{14}{126} =1/9 $
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