(7x+3)/(5x-4)=(3)/(2)

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Solution for (7x+3)/(5x-4)=(3)/(2) equation: 



(7x+3)/(5x-4)=(3)/(2)

We move all terms to the left:

(7x+3)/(5x-4)-((3)/(2))=0



Domain of the equation: (5x-4)!=0

We move all terms containing x to the left, all other terms to the right

5x!=4

x!=4/5

x!=4/5

x∈R



We add all the numbers together, and all the variables

(7x+3)/(5x-4)-(+3/2)=0

We get rid of parentheses

(7x+3)/(5x-4)-3/2=0

We calculate fractions


(14x+6)/(10x-8)+(-15x+12)/(10x-8)=0

We multiply all the terms by the denominator


(14x+6)+(-15x+12)=0

We get rid of parentheses

14x-15x+6+12=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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