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(7x+3)/(5x-4)=3/2
We move all terms to the left:
(7x+3)/(5x-4)-(3/2)=0
Domain of the equation: (5x-4)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
5x!=4
x!=4/5
x!=4/5
x∈R
(7x+3)/(5x-4)-(+3/2)=0
We get rid of parentheses
(7x+3)/(5x-4)-3/2=0
We calculate fractions
(14x+6)/(10x-8)+(-15x+12)/(10x-8)=0
We multiply all the terms by the denominator
(14x+6)+(-15x+12)=0
We get rid of parentheses
14x-15x+6+12=0
We add all the numbers together, and all the variables
-1x+18=0
We move all terms containing x to the left, all other terms to the right
-x=-18
x=-18/-1
x=+18
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