(7x+3)/8=2x+1

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Solution for (7x+3)/8=2x+1 equation:



(7x+3)/8=2x+1
We move all terms to the left:
(7x+3)/8-(2x+1)=0
We get rid of parentheses
(7x+3)/8-2x-1=0
We multiply all the terms by the denominator
(7x+3)-2x*8-1*8=0
We add all the numbers together, and all the variables
(7x+3)-2x*8-8=0
Wy multiply elements
(7x+3)-16x-8=0
We get rid of parentheses
7x-16x+3-8=0
We add all the numbers together, and all the variables
-9x-5=0
We move all terms containing x to the left, all other terms to the right
-9x=5
x=5/-9
x=-5/9

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