(7x+3)=+20-3x/4

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Solution for (7x+3)=+20-3x/4 equation:



(7x+3)=+20-3x/4
We move all terms to the left:
(7x+3)-(+20-3x/4)=0
We add all the numbers together, and all the variables
(7x+3)-(-3x/4+20)=0
We get rid of parentheses
7x+3x/4+3-20=0
We multiply all the terms by the denominator
7x*4+3x+3*4-20*4=0
We add all the numbers together, and all the variables
3x+7x*4-68=0
Wy multiply elements
3x+28x-68=0
We add all the numbers together, and all the variables
31x-68=0
We move all terms containing x to the left, all other terms to the right
31x=68
x=68/31
x=2+6/31

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