(7x+4)(7x+4)=0

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Solution for (7x+4)(7x+4)=0 equation: 



(7x+4)(7x+4)=0

We multiply parentheses ..

(+49x^2+28x+28x+16)=0

We get rid of parentheses

49x^2+28x+28x+16=0

We add all the numbers together, and all the variables

49x^2+56x+16=0

a = 49; b = 56; c = +16;
Δ = b2-4ac
Δ = 562-4·49·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-56}{98}=-4/7$

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