(7x+4)/3=(9x-6)/4

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Solution for (7x+4)/3=(9x-6)/4 equation: 



(7x+4)/3=(9x-6)/4

We move all terms to the left:

(7x+4)/3-((9x-6)/4)=0

We calculate fractions


7x/()+(-((9x-6)*3)/()=0



We calculate terms in parentheses: +(-((9x-6)*3)/(), so:

-((9x-6)*3)/(

We multiply all the terms by the denominator


-((9x-6)*3)



We calculate terms in parentheses: -((9x-6)*3), so:

(9x-6)*3

We multiply parentheses

27x-18

Back to the equation:

-(27x-18)



We get rid of parentheses

-27x+18

Back to the equation:

+(-27x+18)



We get rid of parentheses

7x/()-27x+18=0

We multiply all the terms by the denominator


7x-27x*()+18*()=0

We add all the numbers together, and all the variables

7x-27x*()=0

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