(7x+4)/5=(3x-2)/4

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Solution for (7x+4)/5=(3x-2)/4 equation: 



(7x+4)/5=(3x-2)/4

We move all terms to the left:

(7x+4)/5-((3x-2)/4)=0

We calculate fractions


7x/()+(-((3x-2)*5)/()=0



We calculate terms in parentheses: +(-((3x-2)*5)/(), so:

-((3x-2)*5)/(

We multiply all the terms by the denominator


-((3x-2)*5)



We calculate terms in parentheses: -((3x-2)*5), so:

(3x-2)*5

We multiply parentheses

15x-10

Back to the equation:

-(15x-10)



We get rid of parentheses

-15x+10

Back to the equation:

+(-15x+10)



We get rid of parentheses

7x/()-15x+10=0

We multiply all the terms by the denominator


7x-15x*()+10*()=0

We add all the numbers together, and all the variables

7x-15x*()=0

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