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(7x+40)+(3x+112)=180
We move all terms to the left:
(7x+40)+(3x+112)-(180)=0
We get rid of parentheses
7x+3x+40+112-180=0
We add all the numbers together, and all the variables
10x-28=0
We move all terms containing x to the left, all other terms to the right
10x=28
x=28/10
x=2+4/5
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