(7x+40)=(3x+112)

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Solution for (7x+40)=(3x+112) equation: 



(7x+40)=(3x+112)

We move all terms to the left:

(7x+40)-((3x+112))=0

We get rid of parentheses

7x-((3x+112))+40=0



We calculate terms in parentheses: -((3x+112)), so:

(3x+112)

We get rid of parentheses

3x+112

Back to the equation:

-(3x+112)



We get rid of parentheses

7x-3x-112+40=0

We add all the numbers together, and all the variables

4x-72=0

We move all terms containing x to the left, all other terms to the right

4x=72

x=72/4

x=18

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