(7x+42)+(4x-5)=180

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Solution for (7x+42)+(4x-5)=180 equation: 



(7x+42)+(4x-5)=180

We move all terms to the left:

(7x+42)+(4x-5)-(180)=0

We get rid of parentheses

7x+4x+42-5-180=0

We add all the numbers together, and all the variables

11x-143=0

We move all terms containing x to the left, all other terms to the right

11x=143

x=143/11

x=13

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