(7x+5)+(2x+8)=(3x+19)

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Solution for (7x+5)+(2x+8)=(3x+19) equation: 



(7x+5)+(2x+8)=(3x+19)

We move all terms to the left:

(7x+5)+(2x+8)-((3x+19))=0

We get rid of parentheses

7x+2x-((3x+19))+5+8=0



We calculate terms in parentheses: -((3x+19)), so:

(3x+19)

We get rid of parentheses

3x+19

Back to the equation:

-(3x+19)



We add all the numbers together, and all the variables

9x-(3x+19)+13=0

We get rid of parentheses

9x-3x-19+13=0

We add all the numbers together, and all the variables

6x-6=0

We move all terms containing x to the left, all other terms to the right

6x=6

x=6/6

x=1

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