(7x+5)+(3x+19)=(2x+8)

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Solution for (7x+5)+(3x+19)=(2x+8) equation: 



(7x+5)+(3x+19)=(2x+8)

We move all terms to the left:

(7x+5)+(3x+19)-((2x+8))=0

We get rid of parentheses

7x+3x-((2x+8))+5+19=0



We calculate terms in parentheses: -((2x+8)), so:

(2x+8)

We get rid of parentheses

2x+8

Back to the equation:

-(2x+8)



We add all the numbers together, and all the variables

10x-(2x+8)+24=0

We get rid of parentheses

10x-2x-8+24=0

We add all the numbers together, and all the variables

8x+16=0

We move all terms containing x to the left, all other terms to the right

8x=-16

x=-16/8

x=-2

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