(7x+5)=(2x+35)

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Solution for (7x+5)=(2x+35) equation: 



(7x+5)=(2x+35)

We move all terms to the left:

(7x+5)-((2x+35))=0

We get rid of parentheses

7x-((2x+35))+5=0



We calculate terms in parentheses: -((2x+35)), so:

(2x+35)

We get rid of parentheses

2x+35

Back to the equation:

-(2x+35)



We get rid of parentheses

7x-2x-35+5=0

We add all the numbers together, and all the variables

5x-30=0

We move all terms containing x to the left, all other terms to the right

5x=30

x=30/5

x=6

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