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(7x+6)(7x-45)=0
We multiply parentheses ..
(+49x^2-315x+42x-270)=0
We get rid of parentheses
49x^2-315x+42x-270=0
We add all the numbers together, and all the variables
49x^2-273x-270=0
a = 49; b = -273; c = -270;
Δ = b2-4ac
Δ = -2732-4·49·(-270)
Δ = 127449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{127449}=357$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-273)-357}{2*49}=\frac{-84}{98} =-6/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-273)+357}{2*49}=\frac{630}{98} =6+3/7 $
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