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(7x+6)(x+8)=0
We multiply parentheses ..
(+7x^2+56x+6x+48)=0
We get rid of parentheses
7x^2+56x+6x+48=0
We add all the numbers together, and all the variables
7x^2+62x+48=0
a = 7; b = 62; c = +48;
Δ = b2-4ac
Δ = 622-4·7·48
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2500}=50$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(62)-50}{2*7}=\frac{-112}{14} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(62)+50}{2*7}=\frac{-12}{14} =-6/7 $
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