(7x+6)/4=(2x-3)/5

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Solution for (7x+6)/4=(2x-3)/5 equation: 



(7x+6)/4=(2x-3)/5

We move all terms to the left:

(7x+6)/4-((2x-3)/5)=0

We calculate fractions


7x/()+(-((2x-3)*4)/()=0



We calculate terms in parentheses: +(-((2x-3)*4)/(), so:

-((2x-3)*4)/(

We multiply all the terms by the denominator


-((2x-3)*4)



We calculate terms in parentheses: -((2x-3)*4), so:

(2x-3)*4

We multiply parentheses

8x-12

Back to the equation:

-(8x-12)



We get rid of parentheses

-8x+12

Back to the equation:

+(-8x+12)



We get rid of parentheses

7x/()-8x+12=0

We multiply all the terms by the denominator


7x-8x*()+12*()=0

We add all the numbers together, and all the variables

7x-8x*()=0

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