(7x+60)+(108-3x)=180

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Solution for (7x+60)+(108-3x)=180 equation: 



(7x+60)+(108-3x)=180

We move all terms to the left:

(7x+60)+(108-3x)-(180)=0

We add all the numbers together, and all the variables

(7x+60)+(-3x+108)-180=0

We get rid of parentheses

7x-3x+60+108-180=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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