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(7x+8)(3x-7)=0
We multiply parentheses ..
(+21x^2-49x+24x-56)=0
We get rid of parentheses
21x^2-49x+24x-56=0
We add all the numbers together, and all the variables
21x^2-25x-56=0
a = 21; b = -25; c = -56;
Δ = b2-4ac
Δ = -252-4·21·(-56)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-73}{2*21}=\frac{-48}{42} =-1+1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+73}{2*21}=\frac{98}{42} =2+1/3 $
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