(7x+8)(4x+8)=416

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Solution for (7x+8)(4x+8)=416 equation:



(7x+8)(4x+8)=416
We move all terms to the left:
(7x+8)(4x+8)-(416)=0
We multiply parentheses ..
(+28x^2+56x+32x+64)-416=0
We get rid of parentheses
28x^2+56x+32x+64-416=0
We add all the numbers together, and all the variables
28x^2+88x-352=0
a = 28; b = 88; c = -352;
Δ = b2-4ac
Δ = 882-4·28·(-352)
Δ = 47168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{47168}=\sqrt{64*737}=\sqrt{64}*\sqrt{737}=8\sqrt{737}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-8\sqrt{737}}{2*28}=\frac{-88-8\sqrt{737}}{56} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+8\sqrt{737}}{2*28}=\frac{-88+8\sqrt{737}}{56} $

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