(7x+8)=(x+12)=(3x+20)

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Solution for (7x+8)=(x+12)=(3x+20) equation: 



(7x+8)=(x+12)=(3x+20)

We move all terms to the left:

(7x+8)-((x+12))=0

We get rid of parentheses

7x-((x+12))+8=0



We calculate terms in parentheses: -((x+12)), so:

(x+12)

We get rid of parentheses

x+12

Back to the equation:

-(x+12)



We get rid of parentheses

7x-x-12+8=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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