(7x+9)=((11/2)x+21)

Solution for (7x+9)=((11/2)x+21) equation:

(7x+9)=((11/2)x+21)

We move all terms to the left:

(7x+9)-(((11/2)x+21))=0


Domain of the equation: 2)x+21))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(7x+9)-(((+11/2)x+21))=0

We get rid of parentheses

7x-(((+11/2)x+21))+9=0

We multiply all the terms by the denominator


7x*2)x+21))-(((+9*2)x+21))+11=0

We add all the numbers together, and all the variables

7x*2)x+21))-((18x+21))+11=0

Wy multiply elements

14x^2=0

a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{28}=0$