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(7x-1)(3x+2)=0
We multiply parentheses ..
(+21x^2+14x-3x-2)=0
We get rid of parentheses
21x^2+14x-3x-2=0
We add all the numbers together, and all the variables
21x^2+11x-2=0
a = 21; b = 11; c = -2;
Δ = b2-4ac
Δ = 112-4·21·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*21}=\frac{-28}{42} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*21}=\frac{6}{42} =1/7 $
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