(7x-1)(4x=3)

Solution for (7x-1)(4x=3) equation:

(7x-1)(4x=3)

We move all terms to the left:

(7x-1)(4x-(3))=0

We multiply parentheses ..

(+28x^2-21x-4x+3)=0

We get rid of parentheses

28x^2-21x-4x+3=0

We add all the numbers together, and all the variables

28x^2-25x+3=0

a = 28; b = -25; c = +3;
Δ = b2-4ac
Δ = -252-4·28·3
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-17}{2*28}=\frac{8}{56}
=1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+17}{2*28}=\frac{42}{56}
=3/4
$