(7x-1)=(2x+12)+(2x+5)

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Solution for (7x-1)=(2x+12)+(2x+5) equation: 



(7x-1)=(2x+12)+(2x+5)

We move all terms to the left:

(7x-1)-((2x+12)+(2x+5))=0

We get rid of parentheses

7x-((2x+12)+(2x+5))-1=0



We calculate terms in parentheses: -((2x+12)+(2x+5)), so:

(2x+12)+(2x+5)

We get rid of parentheses

2x+2x+12+5

We add all the numbers together, and all the variables

4x+17

Back to the equation:

-(4x+17)



We get rid of parentheses

7x-4x-17-1=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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