(7x-10)(4x+6)=3948

Solution for (7x-10)(4x+6)=3948 equation:

(7x-10)(4x+6)=3948

We move all terms to the left:

(7x-10)(4x+6)-(3948)=0

We multiply parentheses ..

(+28x^2+42x-40x-60)-3948=0

We get rid of parentheses

28x^2+42x-40x-60-3948=0

We add all the numbers together, and all the variables

28x^2+2x-4008=0

a = 28; b = 2; c = -4008;
Δ = b2-4ac
Δ = 22-4·28·(-4008)
Δ = 448900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{448900}=670$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-670}{2*28}=\frac{-672}{56}
=-12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+670}{2*28}=\frac{668}{56}
=11+13/14
$