(7x-10)+(3x+42)=180

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Solution for (7x-10)+(3x+42)=180 equation:



(7x-10)+(3x+42)=180
We move all terms to the left:
(7x-10)+(3x+42)-(180)=0
We get rid of parentheses
7x+3x-10+42-180=0
We add all the numbers together, and all the variables
10x-148=0
We move all terms containing x to the left, all other terms to the right
10x=148
x=148/10
x=14+4/5

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