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(7x-11)(4x+58)=180
We move all terms to the left:
(7x-11)(4x+58)-(180)=0
We multiply parentheses ..
(+28x^2+406x-44x-638)-180=0
We get rid of parentheses
28x^2+406x-44x-638-180=0
We add all the numbers together, and all the variables
28x^2+362x-818=0
a = 28; b = 362; c = -818;
Δ = b2-4ac
Δ = 3622-4·28·(-818)
Δ = 222660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{222660}=\sqrt{36*6185}=\sqrt{36}*\sqrt{6185}=6\sqrt{6185}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(362)-6\sqrt{6185}}{2*28}=\frac{-362-6\sqrt{6185}}{56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(362)+6\sqrt{6185}}{2*28}=\frac{-362+6\sqrt{6185}}{56} $
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