(7x-11)=(3x-41)

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Solution for (7x-11)=(3x-41) equation: 



(7x-11)=(3x-41)

We move all terms to the left:

(7x-11)-((3x-41))=0

We get rid of parentheses

7x-((3x-41))-11=0



We calculate terms in parentheses: -((3x-41)), so:

(3x-41)

We get rid of parentheses

3x-41

Back to the equation:

-(3x-41)



We get rid of parentheses

7x-3x+41-11=0

We add all the numbers together, and all the variables

4x+30=0

We move all terms containing x to the left, all other terms to the right

4x=-30

x=-30/4

x=-7+1/2

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