(7x-11)=(4x-15)+(4x+19)

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Solution for (7x-11)=(4x-15)+(4x+19) equation: 



(7x-11)=(4x-15)+(4x+19)

We move all terms to the left:

(7x-11)-((4x-15)+(4x+19))=0

We get rid of parentheses

7x-((4x-15)+(4x+19))-11=0



We calculate terms in parentheses: -((4x-15)+(4x+19)), so:

(4x-15)+(4x+19)

We get rid of parentheses

4x+4x-15+19

We add all the numbers together, and all the variables

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

7x-8x-4-11=0

We add all the numbers together, and all the variables

-1x-15=0

We move all terms containing x to the left, all other terms to the right

-x=15

x=15/-1

x=-15

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