(7x-12)=(2x+38)

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Solution for (7x-12)=(2x+38) equation: 



(7x-12)=(2x+38)

We move all terms to the left:

(7x-12)-((2x+38))=0

We get rid of parentheses

7x-((2x+38))-12=0



We calculate terms in parentheses: -((2x+38)), so:

(2x+38)

We get rid of parentheses

2x+38

Back to the equation:

-(2x+38)



We get rid of parentheses

7x-2x-38-12=0

We add all the numbers together, and all the variables

5x-50=0

We move all terms containing x to the left, all other terms to the right

5x=50

x=50/5

x=10

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